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  • SUPPORT THE LEGAL FUND TODAY
  • Impossible Physics
  • Bio-mechanical Impossibility of an Unassisted Fall Causing Eight Rib Fractures
  • 1. The Physics of a Human Fall: Insufficient Force Generation
  • 2. Required Force for Multiple Rib Fractures vs. Human Fall Forces
  • 3. The Role of Impact Acceleration: Why Falling is Not Enough
  • 4. Conclusion: The Physical Impossibility of an 8-Rib Fracture from a Simple Fall
  • Thus, the only reasonable explanation for the injuries sustained is a high-energy external impact, such as a vehicle strike, and not an accidental fall.
  • Biomechanics Analysis
  • Bicycle Fall vs. 6,500 lbs. Vehicle Collision
  • 1. Fundamental Equations (Imperial Units)
  • 2. Bicycle Impact: 5–9 mph
  • 3. Vehicle Impact: 6,500 lb at 10–15 mph
  • 4. Comparison & Rib Fracture Threshold (750–900 lbf)
  • 5. Conclusion
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PHYSICS OF INJURY

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Last updated 3 months ago

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Impossible Physics

Bio-mechanical Impossibility of an Unassisted Fall Causing Eight Rib Fractures

1. The Physics of a Human Fall: Insufficient Force Generation

A human body falling from a standing position onto the ground does not generate the required force to fracture eight ribs because the acceleration and impact energy are too low to reach the necessary impulse threshold. The force exerted during a fall is dictated by the mass of the individual, the height of the fall, the acceleration due to gravity, and the impact surface distribution.

For a 175-pound (79.4 kg) human falling from a height of 6 feet (1.83 meters) (assuming a full standing height impact):

  • The gravitational potential energy at the moment of the fall is given by:

    Ep=mghE_p = mghEp​=mgh

    where:

    • ( m = 79.4 ) kg (175 lbs converted to kg)

    • ( g = 9.81 ) m/s² (acceleration due to gravity)

    • ( h = 1.83 ) m (height of fall)

    Ep=(79.4)(9.81)(1.83)=1,426.4 JoulesE_p = (79.4)(9.81)(1.83) = 1,426.4 \text{ Joules}Ep​=(79.4)(9.81)(1.83)=1,426.4 Joules

  • When the body hits the ground, not all of this energy is directed to the ribs—it is distributed across multiple points of contact (hips, arms, back, shoulders), dissipating the impact.

  • The force experienced depends on the deceleration time. If the impact duration is 0.1 seconds, the average force exerted can be estimated as:

    F=EpdF = \frac{E_p}{d}F=dEp​​

    Assuming a fall directly onto the ribs, the deformation distance of the soft tissue and bones absorbing impact is approximately 3 cm (0.03 m):

    F=1,426.40.03=47,547 NF = \frac{1,426.4}{0.03} = 47,547 \text{ N} F=0.031,426.4​=47,547 N

    However, this is the absolute maximum force if all energy were instantaneously transferred to a single point, which does not happen in real-world falls. Most of the impact is dissipated across multiple body parts, such as arms, hips, and shoulders, significantly reducing the force directed to any one area.

2. Required Force for Multiple Rib Fractures vs. Human Fall Forces

As established earlier, the force required to fracture a single rib is in the range of 1,500–3,000 N (337–674 lbf). The cumulative force needed to fracture eight ribs in separate locations is conservatively estimated at 5,000–10,000 N (1,124–2,248 lbf).

However, when a person falls:

  • The impact force is distributed across the whole body, not concentrated on the ribs.

  • Protective reflexes, such as instinctively extending the arms, further reduce direct rib impact forces.

  • The kinetic energy is partially absorbed by soft tissue, joint flexion, and rotational motion, further dispersing force away from the ribs.

Comparing this to the force required for eight rib fractures, a simple fall to the ground does not produce the necessary force nor the required focused impulse to cause such injuries.

3. The Role of Impact Acceleration: Why Falling is Not Enough

  • Acceleration due to a fall is limited to gravity (9.81 m/s²), meaning that even at terminal velocity from a standing height, the human body does not experience enough rapid deceleration to create a localized high-force impact.

  • By contrast, vehicular trauma or blunt force impacts involve significantly greater accelerations (20-50 times that of gravity in milliseconds), leading to localized forces exceeding 10,000 N—enough to break multiple ribs.

  • Falls produce distributed impact forces, while blunt trauma from a vehicle strike results in a sharp, concentrated force in a small area, which is necessary to create the observed multi-rib fractures.

4. Conclusion: The Physical Impossibility of an 8-Rib Fracture from a Simple Fall

Given the physics of human motion, the mechanics of falls, and the required forces to fracture multiple ribs, it is physically impossible for an unassisted fall from standing height to produce the injuries observed in this case. The force threshold for breaking eight ribs far exceeds what a fall can generate because:

  1. A 175-lbs human does not reach the required force levels through gravitational acceleration alone.

  2. The energy is distributed across multiple contact points, not focused on the ribs.

  3. Reflexive reactions reduce the direct rib impact, preventing concentrated force application.

  4. The required force magnitude and impulse duration exceed those possible in a simple fall but are entirely consistent with vehicular trauma, where a moving object imparts a high-speed, concentrated blow to the ribcage.

Thus, the only reasonable explanation for the injuries sustained is a high-energy external impact, such as a vehicle strike, and not an accidental fall.

Biomechanics Analysis

Bicycle Fall vs. 6,500 lbs. Vehicle Collision

Below is an updated collision analysis comparing:

  1. A bicycle traveling at 5–9 mph

  2. A 6,500 lb vehicle traveling at 10–15 mph

The analysis uses standard imperial units (pounds-force [lbf], feet [ft], miles per hour [mph]).


1. Fundamental Equations (Imperial Units)

    • (F): force (lbf)

    • (m): weight of impacting body (lbs; using weight (\approx) mass(\times g) simplification)

    • (\Delta v): change in velocity (ft/s)

    • (\Delta t): stopping time (s)

    • (KE): energy (ft-lbf)

    • (v): velocity (ft/s)

    • (d): distance (ft)

Unit Conversion Note


2. Bicycle Impact: 5–9 mph

Assumptions:

  • Speed range: 5–9 mph

    • 5 mph (~ 7.3) ft/s

    • 9 mph (~13.2) ft/s

  • Cyclist + bike weight: ~175 lb

  • Stopping distance: ~0.5 ft

2A. Bicycle Impact Force Range

Hence, the peak force ranges from ~12,775 lbf to ~23,100 lbf if the momentum is stopped in 0.1 s.

2B. Bicycle Kinetic Energy Range

Observations (Bicycle)

  • Even though the calculated impulse forces appear in the tens of thousands of lbf, impact spreads over multiple body areas, reducing local rib loading below the ~750–900 lbf/rib fracture threshold.

  • Typical bicycle falls often cause anterior/lateral rib fractures with minimal displacement, leading to a low risk of pneumothorax.


3. Vehicle Impact: 6,500 lb at 10–15 mph

Assumptions:

  • Vehicle weight: 6,500 lb

  • Speed range: 10–15 mph

    • 10 mph ( ~ 14.7) ft/s

    • 15 mph ( ~ 22.0) ft/s

  • Stopping distance: ~3 ft

3A. Vehicle Force Range

3B. Vehicle Kinetic Energy Range

Observations (Vehicle)

  • Even at 10 mph, force ( ~ 478,000) lbf and energy (~ 700,000) ft-lbf.

  • These far exceed the 750–900 lbf/rib fracture threshold, commonly resulting in posterior rib fractures and pneumothorax.


4. Comparison & Rib Fracture Threshold (750–900 lbf)

Factor

Bicycle (5–9 mph)

Vehicle (10–15 mph)

Peak Force (lbf)

12,775–23,100

478,000–715,000

Kinetic Energy (ft-lbf)

4,650–15,300

700,000–1,573,000

Likely Rib Loading

Below threshold

Far above threshold

Fracture Type

Anterior/lateral

Posterior/lateral (displaced)

Pneumothorax Risk

Low

High

Probability of Posterior Rib + Pneumothorax

~10–15%

>90%


5. Conclusion

  1. Bicycle Collision (5–9 mph)

    • Peak impulses in tens of thousands of lbf, but localized rib force is typically below 750–900 lbf due to distribution.

    • Anterior/lateral rib injuries are more common, and pneumothorax is unlikely.

  2. Vehicle Collision (6,500 lb, 10–15 mph)

    • Generates massive forces and energies (hundreds of thousands of lbf, >700k ft-lbf).

    • Far beyond rib fracture thresholds, posterior ribs commonly fractured with pneumothorax.

Bottom Line: The severe injury pattern (multiple posterior rib fractures + pneumothorax) strongly indicates a vehicle collision. Even at 10–15 mph, a 6,500 lb automobile imparts forces and energies that dwarf those from a 5–9 mph bicycle crash, making the vehicular cause the most likely.

Impulse–Momentum (Force) F=m⋅ΔvΔtF = \frac{m \cdot \Delta v}{\Delta t} F=Δtm⋅Δv​

Kinetic Energy KE=12 m v2KE = \frac{1}{2} \, m \, v^2KE=21​mv2

Work ( Force(×)DistanceForce (\times) DistanceForce(×)Distance ) W=F⋅dW = F \cdot dW=F⋅d

1,mph,≈,1.467,ft/s1,\text{mph} ,\approx, 1.467,\text{ft/s}1,mph,≈,1.467,ft/s

Stopping time ( Δt\Delta tΔt ): ~0.1 s

Fbike=m,ΔvΔtF_{\text{bike}} = \frac{m ,\Delta v}{\Delta t} Fbike​=Δtm,Δv​

Lower Speed ( 5 mph(→)7.3 ft/s5 mph (\to) 7.3 ft/s5 mph(→)7.3 ft/s ): F1=175×7.30.1≈12,775,lbf.F_1 = \frac{175 \times 7.3}{0.1} \approx 12{,}775 ,\text{lbf}.F1​=0.1175×7.3​≈12,775,lbf.

Upper Speed ( 9 mph(→)13.2 ft/s9 mph (\to) 13.2 ft/s9 mph(→)13.2 ft/s ): F2=175×13.20.1≈23,100,lbfF_2 = \frac{175 \times 13.2}{0.1} \approx 23{,}100 ,\text{lbf}F2​=0.1175×13.2​≈23,100,lbf

KEbike=12,m,v2KE_{\text{bike}} = \frac{1}{2} , m , v^2 KEbike​=21​,m,v2

At 5 mph (7.3 ft/s): KE1=12×175×(7.3)2≈4,650,ft-lbfKE_1 = \tfrac{1}{2} \times 175 \times (7.3)^2 \approx 4{,}650 ,\text{ft-lbf}KE1​=21​×175×(7.3)2≈4,650,ft-lbf

At 9 mph (13.2 ft/s): KE2=12×175×(13.2)2≈15,300,ft-lbfKE_2 = \tfrac{1}{2} \times 175 \times (13.2)^2 \approx 15{,}300 ,\text{ft-lbf}KE2​=21​×175×(13.2)2≈15,300,ft-lbf

Stopping time ( Δt\Delta tΔt ): ~0.2 s

Fvehicle=m,ΔvΔtF_{\text{vehicle}} = \frac{m ,\Delta v}{\Delta t} Fvehicle​=Δtm,Δv​

At 10 mph (14.7 ft/s): F10mph=6,500×14.70.2≈478,000,lbfF_{\text{10mph}} = \frac{6{,}500 \times 14.7}{0.2} \approx 478{,}000 ,\text{lbf}F10mph​=0.26,500×14.7​≈478,000,lbf

At 15 mph (22.0 ft/s): F15mph=6,500×22.00.2≈715,000,lbfF_{\text{15mph}} = \frac{6{,}500 \times 22.0}{0.2} \approx 715{,}000 ,\text{lbf}F15mph​=0.26,500×22.0​≈715,000,lbf

KEvehicle=12,m,v2KE_{\text{vehicle}} = \frac{1}{2}, m, v^2KEvehicle​=21​,m,v2

At 10 mph (14.7 ft/s): KE10mph=12×6,500×(14.7)2≈700,000,ft-lbfKE_{\text{10mph}} = \tfrac{1}{2} \times 6{,}500 \times (14.7)^2 \approx 700{,}000 ,\text{ft-lbf}KE10mph​=21​×6,500×(14.7)2≈700,000,ft-lbf

At 15 mph (22.0 ft/s): KE15mph=12×6,500×(22.0)2≈1,573,000,ft-lbfKE_{\text{15mph}} = \tfrac{1}{2} \times 6{,}500 \times (22.0)^2 \approx 1{,}573{,}000 ,\text{ft-lbf}KE15mph​=21​×6,500×(22.0)2≈1,573,000,ft-lbf

At 15 mph, force ( ~ 715,000) lbf, energy ( ≈1.57×106\approx 1.57 \times 10^6≈1.57×106 ) ft-lbf.

https://www.spotfund.com/story/88e93d31-3915-409e-b4ac-e29a5d1fd6d6